1.If RRR is the relation "<<<" from A={1,2,3,4}A = \{1, 2, 3, 4\}A={1,2,3,4} to B={1,3,5}B = \{1, 3, 5\}B={1,3,5}, i.e. (a,b)∈R(a, b) \in R(a,b)∈R iff a<ba < ba<b, then R∘R−1R \circ R^{-1}R∘R−1 isa.{(1,3),(1,5),(2,3),(2,5),(3,5),(4,5)}\{(1, 3), (1, 5), (2, 3), (2, 5), (3, 5), (4, 5)\}{(1,3),(1,5),(2,3),(2,5),(3,5),(4,5)}b.{(3,1),(5,1),(3,2),(5,2),(5,3),(5,4)}\{(3, 1), (5, 1), (3, 2), (5, 2), (5, 3), (5, 4)\}{(3,1),(5,1),(3,2),(5,2),(5,3),(5,4)}c.{(3,3),(3,5),(5,3),(5,5)}\{(3, 3), (3, 5), (5, 3), (5, 5)\}{(3,3),(3,5),(5,3),(5,5)}d.{(3,3),(3,4),(4,5)}\{(3, 3), (3, 4), (4, 5)\}{(3,3),(3,4),(4,5)}Login to continueOnly logged in users canattempt or see the solution.
