1.A random variable XXX follows a binomial distribution B(n,p)B(n, p)B(n,p) for which the difference of the mean and the variance is 111. If 2P(X=2)=3P(X=1)2P(X = 2) = 3P(X = 1)2P(X=2)=3P(X=1), then n2 P(X>1)n^{2}\, P(X > 1)n2P(X>1) is equal to:a.151515b.111111c.121212d.161616Login to continueOnly logged in users canattempt or see the solution.
