1.If 202−3x2=(405)3x2−220^{2-3x^2} = (40\sqrt{5})^{3x^2-2}202−3x2=(405)3x2−2, then xxx is equal toa.±3/2\pm \sqrt{3/2}±3/2b.±2/3\pm \sqrt{2/3}±2/3c.±4/3\pm \sqrt{4/3}±4/3d.±5/4\pm \sqrt{5/4}±5/4Login to continueOnly logged in users canattempt or see the solution.
