1.A tangent is drawn to the curve y=8x2y = \frac{8}{x^2}y=x28 at a point A(x1,y1)A(x_1, y_1)A(x1,y1), where x1=2x_1 = 2x1=2. The tangent cuts the xxx-axis at point BBB. Then the scalar product of the vectors AB→\overrightarrow{AB}AB and OB→\overrightarrow{OB}OB isa.333b.−3-3−3c.666d.−6-6−6Login to continueOnly logged in users canattempt or see the solution.