1.The equation of state for 2 g2\,\text{g}2g of oxygen at a pressure PPP and temperature TTT, when occupying a volume VVV will bea.PV=116RTPV = \frac{1}{16}RTPV=161RTb.PV=RT16PV = \frac{RT}{16}PV=16RTc.PV=RT32PV = \frac{RT}{32}PV=32RTd.PV=232RTPV = \frac{2}{32}RTPV=322RTLogin to continueOnly logged in users canattempt or see the solution.
