1.For the variable ttt, the locus of the point of intersection of 3tx−2y+6t=03tx - 2y + 6t = 03tx−2y+6t=0 and 3x+2ty−6=03x + 2ty - 6 = 03x+2ty−6=0 isa.the ellipse x24+y29=1\frac{x^2}{4} + \frac{y^2}{9} = 14x2+9y2=1b.the ellipse x29+y24=1\frac{x^2}{9} + \frac{y^2}{4} = 19x2+4y2=1c.the hyperbola x24−y29=1\frac{x^2}{4} - \frac{y^2}{9} = 14x2−9y2=1d.the hyperbola x29−y24=1\frac{x^2}{9} - \frac{y^2}{4} = 19x2−4y2=1Login to continueOnly logged in users canattempt or see the solution.
