1.Solution of edy/dx=xe^{dy/dx} = xedy/dx=x when x=1x = 1x=1 and y=0y = 0y=0 isa.y=x(logx−1)+4y = x(\log x - 1) + 4y=x(logx−1)+4b.y=x(logx−1)+3y = x(\log x - 1) + 3y=x(logx−1)+3c.y=x(logx+1)+1y = x(\log x + 1) + 1y=x(logx+1)+1d.y=x(logx−1)+1y = x(\log x - 1) + 1y=x(logx−1)+1Login to continueOnly logged in users canattempt or see the solution.
