1.A simple harmonic motion having an amplitude AAA and time period TTT is represented by the equation:y=5sinπ(t+4) my = 5\sin\pi(t + 4)\,\text{m}y=5sinπ(t+4)mThen the values of AAA (in m) and TTT (in sec) are:a.A=5A = 5A=5; T=2T = 2T=2b.A=10A = 10A=10; T=1T = 1T=1c.A=5A = 5A=5; T=1T = 1T=1d.A=10A = 10A=10; T=2T = 2T=2Login to continueOnly logged in users canattempt or see the solution.