1.Let α\alphaα and β\betaβ be the roots of x2−3x+p=0x^2 - 3x + p = 0x2−3x+p=0 and γ\gammaγ and δ\deltaδ be the roots of x2−6x+q=0x^2 - 6x + q = 0x2−6x+q=0. If α,β,γ,δ\alpha, \beta, \gamma, \deltaα,β,γ,δ form a geometric progression, then ratio (2q+p):(2q−p)(2q + p) : (2q - p)(2q+p):(2q−p) is:a.3:13 : 13:1b.9:79 : 79:7c.5:35 : 35:3d.33:3133 : 3133:31Login to continueOnly logged in users canattempt or see the solution.