1.If 2⋅310+22⋅39+⋯+210⋅3=6K2 \cdot 3^{10} + 2^{2} \cdot 3^{9} + \cdots + 2^{10} \cdot 3 = 6K2⋅310+22⋅39+⋯+210⋅3=6K, then the remainder when KKK is divided by 666 isa.222b.333c.444d.555Login to continueOnly logged in users canattempt or see the solution.
