1.
Let α=3i^+j^\vec{\alpha} = 3\hat{i} + \hat{j} and β=2i^j^+3k^\vec{\beta} = 2\hat{i} - \hat{j} + 3\hat{k}. If β=β1β2\vec{\beta} = \vec{\beta}_1 - \vec{\beta}_2, where β1\vec{\beta}_1 is parallel to α\vec{\alpha} and β2\vec{\beta}_2 is perpendicular to α\vec{\alpha}, then β1×β2\vec{\beta}_1 \times \vec{\beta}_2 is equal to
Vector Algebra - Hard - Question