1.If P(−3,2)P(-3,2)P(−3,2) is one end of the focal chord PQPQPQ of the parabola (y+2)2=−4(x−1)(y + 2)^2 = -4(x - 1)(y+2)2=−4(x−1), then the slope of the normal at QQQ isa.−12-\frac{1}{2}−21b.222c.12\frac{1}{2}21d.−2-2−2Login to continueOnly logged in users canattempt or see the solution.
