1.Let ∗,□∈{∧,∨}*, \square \in \{\wedge, \vee\}∗,□∈{∧,∨} be such that the Boolean expression (p∗¬q)⇔(p□q)(p * \neg q) \Leftrightarrow (p \square q)(p∗¬q)⇔(p□q) is a tautology. Then:a.∗=∨* = \vee∗=∨, □=∧\square = \wedge□=∧b.∗=∨* = \vee∗=∨, □=∨\square = \vee□=∨c.∗=∧* = \wedge∗=∧, □=∨\square = \vee□=∨d.∗=∧* = \wedge∗=∧, □=∧\square = \wedge□=∧Login to continueOnly logged in users canattempt or see the solution.
