1.Let f(x)f(x)f(x) be a real differentiable function such that f(0)=1f(0) = 1f(0)=1 and f(x+y)=f(x)f′(y)+f′(x)f(y)f(x + y) = f(x)f'(y) + f'(x)f(y)f(x+y)=f(x)f′(y)+f′(x)f(y) for all x,y∈Rx, y \in \mathbb{R}x,y∈R. Then logef(5050)\log_e f(5050)logef(5050) is equal to:a.252525252525b.522052205220c.238423842384d.240624062406Login to continueOnly logged in users canattempt or see the solution.
