1.Let A=(21012−10−12)A = \begin{pmatrix} 2 & 1 & 0 \\ 1 & 2 & -1 \\ 0 & -1 & 2 \end{pmatrix}A=21012−10−12. If ∣adj(adj(adj(2A)))∣=(16)n\left|\text{adj}\bigl(\text{adj}(\text{adj}(2A))\bigr)\right| = (16)^{n}adj(adj(adj(2A)))=(16)n, then nnn is equal to:a.888b.101010c.999d.121212Login to continueOnly logged in users canattempt or see the solution.
