1.If ∫f(x)log(sinx)dx=log[logsinx]+c\int \frac{f(x)}{\log(\sin x)} dx = \log[\log\sin x] + c∫log(sinx)f(x)dx=log[logsinx]+c, then f(x)=f(x) =f(x)=a.\cot xb.\tan xc.\sec xd.\cosec xLogin to continueOnly logged in users canattempt or see the solution.
