1.An experiment measures quantities xxx, yyy, zzz and then ttt is calculated from the data as t=xy2z3t = \dfrac{xy^2}{z^3}t=z3xy2. If percentage errors in xxx, yyy and zzz are respectively 1%1\%1%, 3%3\%3%, 2%2\%2%, then the percentage error in ttt isa.10%10\%10%b.4%4\%4%c.7%7\%7%d.13%13\%13%Login to continueOnly logged in users canattempt or see the solution.