1.0.2 + 0.22 + 0.222 + ... upto n terms is equal toa.(2/9)[n - (1/9)(1 - 10^{-n})]b.(2/9)[n - (1/9)(1 - 10^{-n})]c.(2/81)[9n - (1 - 10^{-n})]d.(2/81)[9n + (1 + 10^{-n})]Login to continueOnly logged in users canattempt or see the solution.
