1.Suppose f:R→(0,∞)f : \mathbb{R} \to (0, \infty)f:R→(0,∞) is a differentiable function such that 5f(x+y)=f(x)f(y)5f(x + y) = f(x)f(y)5f(x+y)=f(x)f(y), x,y∈Rx, y \in \mathbb{R}x,y∈R. If f(3)=320f(3) = 320f(3)=320, then ∑n=05f(n)\sum_{n=0}^{5} f(n)∑n=05f(n) is equal toLogin to continueOnly logged in users canattempt or see the solution.
