1.If the fourth term in the binomial expansion of (1+xlog2x)7\left(1 + x^{\log_2 x}\right)^7(1+xlog2x)7, x>0x > 0x>0, is 20⋅8720 \cdot 8^720⋅87, then a possible value of xxx isa.8−28^{-2}8−2b.838^{3}83c.81/38^{1/3}81/3d.828^{2}82Login to continueOnly logged in users canattempt or see the solution.