1.If f(x)={log(1+2ax)−log(1−bx)x,x≠0k,x=0f(x)=\begin{cases}\frac{\log(1+2ax)-\log(1-bx)}{x},&x\ne0\\k,&x=0\end{cases}f(x)={xlog(1+2ax)−log(1−bx),k,x=0x=0 continuous at 000, find kkka.b+ab+ab+ab.b−2ab-2ab−2ac.2a−b2a-b2a−bd.2a+b2a+b2a+bLogin to continueOnly logged in users canattempt or see the solution.
