1.If the system of linear equations2x+y−z=7,2x + y - z = 7,2x+y−z=7,x−3y+2z=1,x - 3y + 2z = 1,x−3y+2z=1,x+4y+θz=k,x + 4y + \theta z = k,x+4y+θz=k,where θ,k∈R\theta, k \in \mathbb{R}θ,k∈R has infinitely many solutions, then θ+k\theta + kθ+k is equal to:a.−3-3−3b.333c.666d.999Login to continueOnly logged in users canattempt or see the solution.