1.A circuit is made up of a resistance 12 Ω12\,\Omega12Ω and inductance 0.01 H0.01\,\text{H}0.01H. An alternating emf of 200 V200\,\text{V}200V, 50 Hz50\,\text{Hz}50Hz is connected in the circuit. The phase difference between the current and emf in the circuit isa.tan−1(π)\tan^{-1}(\pi)tan−1(π)b.tan−1 (π12)\tan^{-1}\!\left(\dfrac{\pi}{12}\right)tan−1(12π)c.tan−1(λ)\tan^{-1}(\lambda)tan−1(λ)d.tan−1(1)\tan^{-1}(1)tan−1(1)Login to continueOnly logged in users canattempt or see the solution.