1.A triangle ABCABCABC is formed by the lines 2x−3y−6=02x - 3y - 6 = 02x−3y−6=0, 3x−y+3=03x - y + 3 = 03x−y+3=0 and 3x+4y−12=03x + 4y - 12 = 03x+4y−12=0. If the points P(α,0)P(\alpha, 0)P(α,0) and Q(0,β)Q(0, \beta)Q(0,β) always lie on or inside △ABC\triangle ABC△ABC, thena.α∈[−1,2]\alpha \in [-1,2]α∈[−1,2] and β∈[−2,3]\beta \in [-2,3]β∈[−2,3]b.α∈[−1,3]\alpha \in [-1,3]α∈[−1,3] and β∈[−2,4]\beta \in [-2,4]β∈[−2,4]c.α∈[−2,4]\alpha \in [-2,4]α∈[−2,4] and β∈[−3,4]\beta \in [-3,4]β∈[−3,4]d.α∈[−1,3]\alpha \in [-1,3]α∈[−1,3] and β∈[−2,3]\beta \in [-2,3]β∈[−2,3]Login to continueOnly logged in users canattempt or see the solution.
