1.If ∣a⃗∣=2|\vec{a}| = 2∣a∣=2, ∣b⃗∣=3|\vec{b}| = 3∣b∣=3 and a⃗\vec{a}a, b⃗\vec{b}b are mutually perpendicular, then the area of the triangle whose vertices are 0⃗\vec{0}0, a⃗+b⃗\vec{a} + \vec{b}a+b, a⃗−b⃗\vec{a} - \vec{b}a−b isa.555b.111c.666d.888Login to continueOnly logged in users canattempt or see the solution.