1.When ∣A⃗+B⃗∣=∣A⃗−B⃗∣|\vec{A} + \vec{B}| = |\vec{A} - \vec{B}|∣A+B∣=∣A−B∣, then A⃗⋅B⃗\vec{A} \cdot \vec{B}A⋅B is equal to:a.000b.ABABABc.111d.Zero vectorLogin to continueOnly logged in users canattempt or see the solution.
