1.If a ball is thrown vertically with speed uuu, the distance covered during the last ttt seconds of its ascent is:a.utututb.12gt2\frac{1}{2}gt^221gt2c.ut−12gt2ut - \frac{1}{2}gt^2ut−21gt2d.(u+gt)t(u + gt)t(u+gt)tLogin to continueOnly logged in users canattempt or see the solution.
