1.Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1,a2,a3,… be an A.P. such that a1+a2+⋯+apa1+a2+a3+⋯+aq=a6a21\dfrac{a_1 + a_2 + \cdots + a_p}{a_1 + a_2 + a_3 + \cdots + a_q} = \dfrac{a_6}{a_{21}}a1+a2+a3+⋯+aqa1+a2+⋯+ap=a21a6, where p≠qp \neq qp=q. Then a6a21\dfrac{a_6}{a_{21}}a21a6 is equal to:a.1211861\dfrac{121}{1861}1861121b.1141\dfrac{11}{41}4111c.1211681\dfrac{121}{1681}1681121d.4111\dfrac{41}{11}1141Login to continueOnly logged in users canattempt or see the solution.
