1.Equation of circle of radius 555 touching coordinate axes in third quadranta.(x−5)2+(y+5)2=25(x-5)^2+(y+5)^2=25(x−5)2+(y+5)2=25b.(x+5)2+(y+5)2=25(x+5)^2+(y+5)^2=25(x+5)2+(y+5)2=25c.(x+4)2+(y+4)2=25(x+4)^2+(y+4)^2=25(x+4)2+(y+4)2=25d.(x+6)2+(y+6)2=25(x+6)^2+(y+6)^2=25(x+6)2+(y+6)2=25Login to continueOnly logged in users canattempt or see the solution.
