1.limx→∞(x2−2x+1x2−4x+2)x\displaystyle\lim_{x\to\infty}\left(\frac{x^2-2x+1}{x^2-4x+2}\right)^xx→∞lim(x2−4x+2x2−2x+1)x isa.e2e^2e2b.e−2e^{-2}e−2c.e6e^6e6d.None of theseLogin to continueOnly logged in users canattempt or see the solution.