1.The ratio of number of oxygen atoms (O) in 16.0 g ozone (O3\text{O}_3O3), 28.0 g carbon monoxide (CO) and 16.0 g oxygen (O2\text{O}_2O2) is (Atomic mass: C = 12, O = 16 and Avogadro's constant NA=6.0×1023 mol−1\text{N}_\text{A} = 6.0 \times 10^{23}\ \text{mol}^{-1}NA=6.0×1023 mol−1)a.3 : 1 : 2b.1 : 1 : 2c.3 : 1 : 1d.1 : 1 : 1Login to continueOnly logged in users canattempt or see the solution.