1.Let A=(2−102)A = \begin{pmatrix} 2 & -1 \\ 0 & 2 \end{pmatrix}A=(20−12). If B=I−5C1(adj A)+5C2(adj A)2−5C3(adj A)3+5C4(adj A)4−5C5(adj A)5B = I - {}^5C_1(\text{adj}\, A) + {}^5C_2(\text{adj}\, A)^2 - {}^5C_3(\text{adj}\, A)^3 + {}^5C_4(\text{adj}\, A)^4 - {}^5C_5(\text{adj}\, A)^5B=I−5C1(adjA)+5C2(adjA)2−5C3(adjA)3+5C4(adjA)4−5C5(adjA)5, then the sum of all elements of the matrix BBB is:a.−5-5−5b.−6-6−6c.−7-7−7d.−8-8−8Login to continueOnly logged in users canattempt or see the solution.
