1.Let the system of linear equations−x+2y+9z=7,-x + 2y + 9z = 7,−x+2y+9z=7,−x+3y+7z=9,-x + 3y + 7z = 9,−x+3y+7z=9,−2x+y+5z=8,-2x + y + 5z = 8,−2x+y+5z=8,−3x+y+13z=A-3x + y + 13z = A−3x+y+13z=Ahave a unique solution x=α,y=β,z=γx = \alpha, y = \beta, z = \gammax=α,y=β,z=γ. Then the distance of the point (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) from the plane 2x−2y+z=A2x - 2y + z = A2x−2y+z=A isa.11b.7c.9d.13Login to continueOnly logged in users canattempt or see the solution.