1.Let α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R and let A=(βα3ααβ−βα2α)A = \begin{pmatrix} \beta & \alpha & 3 \\ \alpha & \alpha & \beta \\ -\beta & \alpha & 2\alpha \end{pmatrix}A=βα−βααα3β2α. If B=(3α−93α−α72α−2α5−28)B = \begin{pmatrix} 3\alpha & -9 & 3\alpha \\ -\alpha & 7 & 2\alpha \\ -2\alpha & 5 & -28 \end{pmatrix}B=3α−α−2α−9753α2α−28 is the matrix of cofactors of the elements of AAA, then det(AB)\det(AB)det(AB) is equal to:a.646464b.216216216c.343343343d.125125125Login to continueOnly logged in users canattempt or see the solution.
