1.Let A=[0α00]A = \begin{bmatrix}0&\alpha\\0&0\end{bmatrix}A=[00α0] and (A+I)50−50A=[abcd](A+I)^{50}-50A = \begin{bmatrix}a&b\\c&d\end{bmatrix}(A+I)50−50A=[acbd]. Find abc+abd+bcd+acdabc+abd+bcd+acdabc+abd+bcd+acda.000b.−1-1−1c.111d.NoneLogin to continueOnly logged in users canattempt or see the solution.
