1.f(x)=∣x∣f(x)=|x|f(x)=∣x∣, g(x)=[x]g(x)=[x]g(x)=[x], (f∘g)′(−1)=(f\circ g)'(-1)=(f∘g)′(−1)=a.0b.does not existc.-1d.1Login to continueOnly logged in users canattempt or see the solution.
