1.One mole of an ideal gas (CV=20C_V = 20CV=20 JK−1^{-1}−1 mol−1^{-1}−1) initially at STP is heated at constant volume to twice the initial temperature. For the process, WWW and qqq will be:a.W=0;q=5.46W = 0; q = 5.46W=0;q=5.46 kJb.W=0;q=0W = 0; q = 0W=0;q=0c.W=−5.46W = -5.46W=−5.46 kJ; q=5.46q = 5.46q=5.46 kJd.W=5.46W = 5.46W=5.46 kJ; q=5.46q = 5.46q=5.46 kJLogin to continueOnly logged in users canattempt or see the solution.