1.∣(x2+1)2(xy+1)2(xz+1)2(xy+1)2(y2+1)2(yz+1)2(xz+1)2(yz+1)2(z2+1)2∣=k(x−y)2(y−z)2(z−x)2\begin{vmatrix} (x^2+1)^2 & (xy+1)^2 & (xz+1)^2 \\ (xy+1)^2 & (y^2+1)^2 & (yz+1)^2 \\ (xz+1)^2 & (yz+1)^2 & (z^2+1)^2 \end{vmatrix} = k(x-y)^2(y-z)^2(z-x)^2(x2+1)2(xy+1)2(xz+1)2(xy+1)2(y2+1)2(yz+1)2(xz+1)2(yz+1)2(z2+1)2=k(x−y)2(y−z)2(z−x)2, then k=k =k=a.111b.222c.333d.444Login to continueOnly logged in users canattempt or see the solution.
