1.The equation of the circle through (1,0),(0,−6),(3,4)(1,0),(0,-6),(3,4)(1,0),(0,−6),(3,4) isa.4x2+4y2+142x+47y+140=04x^2+4y^2+142x+47y+140=04x2+4y2+142x+47y+140=0b.4x2+4y2−142x−47y+138=04x^2+4y^2-142x-47y+138=04x2+4y2−142x−47y+138=0c.4x2+4y2−142x+47y+138=04x^2+4y^2-142x+47y+138=04x2+4y2−142x+47y+138=0d.4x2+4y2+150x−49y+138=04x^2+4y^2+150x-49y+138=04x2+4y2+150x−49y+138=0Login to continueOnly logged in users canattempt or see the solution.
