1.In triangle ABCABCABC, if AC=8AC = 8AC=8, BC=7BC = 7BC=7 and DDD lies between AAA and BBB such that AD=2AD = 2AD=2, BD=4BD = 4BD=4, then the length CDCDCD equalsa.46\sqrt{46}46b.48\sqrt{48}48c.51\sqrt{51}51d.75\sqrt{75}75Login to continueOnly logged in users canattempt or see the solution.