1.The general solution of (x2+xy)y′=y2(x^2 + xy)y' = y^2(x2+xy)y′=y2 isa.ey/x=cxe^{y/x} = cxey/x=cxb.cy=e−y/xc y = e^{-y/x}cy=e−y/xc.e−y/x=cxye^{-y/x} = cxye−y/x=cxyd.e−2y/x=cye^{-2y/x} = cye−2y/x=cyLogin to continueOnly logged in users canattempt or see the solution.
