1.If f(x)={∫0x(5+∣1−t∣) dt,x>25x+1,x≤2f(x) = \begin{cases} \int_{0}^{x} (5+|1-t|) \, dt, & x > 2 \\ 5x+1, & x \leq 2 \end{cases}f(x)={∫0x(5+∣1−t∣)dt,5x+1,x>2x≤2, then:Login to continueOnly logged in users canattempt or see the solution.
