1.If u⃗=a⃗−b⃗\vec{u} = \vec{a} - \vec{b}u=a−b and v⃗=a⃗+b⃗\vec{v} = \vec{a} + \vec{b}v=a+b and ∣a⃗∣=∣b⃗∣=2|\vec{a}| = |\vec{b}| = 2∣a∣=∣b∣=2, then ∣u⃗×v⃗∣|\vec{u} \times \vec{v}|∣u×v∣ is equal toa.216−(a⃗⋅b⃗)22\sqrt{16 - (\vec{a}\cdot\vec{b})^2}216−(a⋅b)2b.16−(a⃗⋅b⃗)2\sqrt{16 - (\vec{a}\cdot\vec{b})^2}16−(a⋅b)2c.24−(a⃗⋅b⃗)22\sqrt{4 - (\vec{a}\cdot\vec{b})^2}24−(a⋅b)2d.24+(a⃗⋅b⃗)22\sqrt{4 + (\vec{a}\cdot\vec{b})^2}24+(a⋅b)2Login to continueOnly logged in users canattempt or see the solution.
