1.The solution of the equation (x−4y3) dy−y dx=0(x - 4y^3)\,dy - y\,dx = 0(x−4y3)dy−ydx=0, (y>0y > 0y>0) isa.x=y3+cyx = y^3 + cyx=y3+cyb.x+2y=cyx + 2y = cyx+2y=cyc.y=x3+cxy = x^3 + cxy=x3+cxd.y+2x3=cxy + 2x^3 = cxy+2x3=cxLogin to continueOnly logged in users canattempt or see the solution.