1.The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0a_0a0 is Bohr radius]:a.h24π2ma02\frac{h^2}{4\pi^2 m a_0^2}4π2ma02h2b.h216π2ma02\frac{h^2}{16\pi^2 m a_0^2}16π2ma02h2c.h232π2ma02\frac{h^2}{32\pi^2 m a_0^2}32π2ma02h2d.h264π2ma02\frac{h^2}{64\pi^2 m a_0^2}64π2ma02h2Login to continueOnly logged in users canattempt or see the solution.