1.Given a parallelogram OACB. The lengths of the vectors OA⃗\vec{OA}OA, OB⃗\vec{OB}OB and AB⃗\vec{AB}AB are aaa, bbb and ccc respectively. The scalar product of the vectors OC⃗\vec{OC}OC and OB⃗\vec{OB}OB isa.a2−3b2+c22\dfrac{a^2 - 3b^2 + c^2}{2}2a2−3b2+c2b.3a2+b2−c22\dfrac{3a^2 + b^2 - c^2}{2}23a2+b2−c2c.3a2−b2+c22\dfrac{3a^2 - b^2 + c^2}{2}23a2−b2+c2d.a2+3b2−c22\dfrac{a^2 + 3b^2 - c^2}{2}2a2+3b2−c2Login to continueOnly logged in users canattempt or see the solution.
