1.limx→0+xsin−1(2x1+x2)cos−1(1−x21+x2)tan−1(3x−x31−3x2)\displaystyle\lim_{x\to0^+}\frac{x\sin^{-1}\left(\frac{2x}{1+x^2}\right)}{\cos^{-1}\left(\frac{1-x^2}{1+x^2}\right)\tan^{-1}\left(\frac{3x-x^3}{1-3x^2}\right)}x→0+limcos−1(1+x21−x2)tan−1(1−3x23x−x3)xsin−1(1+x22x) is equal toa.1/21/21/2b.1/31/31/3c.1/41/41/4d.1/61/61/6Login to continueOnly logged in users canattempt or see the solution.