1.Let f(x)+2f(1x)=x2+5f(x) + 2f\left(\frac{1}{x}\right) = x^2 + 5f(x)+2f(x1)=x2+5 and 2g(x)−3g(12)=x2g(x) - 3g\left(\frac{1}{2}\right) = x2g(x)−3g(21)=x, x>0x > 0x>0. If α=∫12f(x)dx\alpha = \int_1^2 f(x) dxα=∫12f(x)dx and β=∫12g(x)dx\beta = \int_1^2 g(x) dxβ=∫12g(x)dx, then the value of 9α+β9\alpha + \beta9α+β is:Login to continueOnly logged in users canattempt or see the solution.
