1.adj[102−11−2021]=[5a−2110−2−2b]\text{adj}\begin{bmatrix}1&0&2\\-1&1&-2\\0&2&1\end{bmatrix} = \begin{bmatrix}5&a&-2\\1&1&0\\-2&-2&b\end{bmatrix}adj1−100122−21=51−2a1−2−20b, then [a b]=[a\;b] =[ab]=a.[−4 1][-4\;1][−41]b.[−4 −1][-4\;-1][−4−1]c.[4 1][4\;1][41]d.[4 −1][4\;-1][4−1]Login to continueOnly logged in users canattempt or see the solution.
