1.If a⃗\vec{a}a is a vector of magnitude 50, collinear with the vector b⃗=6i^−8j^−152k^\vec{b} = 6\hat{i} - 8\hat{j} - \frac{15}{2}\hat{k}b=6i^−8j^−215k^ and makes an acute angle with the positive direction of Z-axis, then a⃗\vec{a}a is equal toa.−24i^+32j^+30k^-24\hat{i} + 32\hat{j} + 30\hat{k}−24i^+32j^+30k^b.24i^−32j^−30k^24\hat{i} - 32\hat{j} - 30\hat{k}24i^−32j^−30k^c.−12i^+16j^−15k^-12\hat{i} + 16\hat{j} - 15\hat{k}−12i^+16j^−15k^d.12i^−16j^−15k^12\hat{i} - 16\hat{j} - 15\hat{k}12i^−16j^−15k^Login to continueOnly logged in users canattempt or see the solution.